Engineering Board Exam Reviewer · Second-Order Linear Homogeneous Equations · medium
Find the differential equation whose general solution is y=C1ex+C2e3x.
- y''+4y'+3y=0
- y''-3y'+4y=0
- y''-4y'+3y=0
- y''-4y'-3y=0
Answer
C. y''-4y'+3y=0
Solution
The roots are r=1 and r=3, so the characteristic equation is (r-1)(r-3)=r2-4r+3=0. The differential equation is y''-4y'+3y=0.
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