Engineering Board Exam Reviewer · Second-Order Linear Homogeneous Equations · medium

Find the general solution of y''-2y'+2y=0.

1. y = ≤ft(C1 x + C2 x ) e- x
2. y = ≤ft(C1 x + C2 x ) ex
3. y = ≤ft(C1 2 x + C2 2 x ) ex
4. y = ≤ft(C1 x + C2 x ) e2 x

Answer

B. y = ≤ft(C1 x + C2 x ) ex

Solution

r= 2 (4-8)2=1 i, so y=ex(C1 x+C2 x).

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