Engineering Board Exam Reviewer · Trigonometric Integrals and Substitution · medium

Evaluate: 4≤ft(x ),dx

  1. 3 x/8 + ≤ft(2 x )4 + ≤ft(4 x )32+C
  2. 3 x/8 - ≤ft(2 x )4 + ≤ft(4 x )32+C
  3. x/2 + ≤ft(2 x )4 + ≤ft(4 x )32+C
  4. ≤ft(x ) 5≤ft(x )5+C

Answer

A. 3 x/8 + ≤ft(2 x )4 + ≤ft(4 x )32+C

Solution

4x=≤ft(1+ 2x/2 )2=3/8+ 2x/2+ 4x/8. Integrating: 3x/8+ 2x/4+ 4x/32+C.

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