Engineering Board Exam Reviewer · Trigonometric Integrals and Substitution · medium

Evaluate: 1x2 + 4 x + 13,dx

1. ≤ft(x/3 + 2/3 )+C
2. ≤ft(x/3 + 2/3 )3+C
3. ≤ft(x + 2 )3+C
4. ≤ft(x/3 + 2/3 )9+C

Answer

B. ≤ft(x/3 + 2/3 )3+C

Solution

Complete the square: x2+4x+13=(x+2)2+9. Then /(x+2)2+32= 13 +2/3+C.

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