Engineering Board Exam Reviewer · Trigonometric Integrals and Substitution · hard

Evaluate: x2 - 16x,dx (for x>4)

1. x2 - 16 - 4 ≤ft(4/x )+C
2. x2 - 16 + 4 ≤ft(4/x )+C
3. x2 - 16 - 4 ≤ft(4/x )+C
4. 2 x2 - 16 - 4 ≤ft(4/x )+C

Answer

A. x2 - 16 - 4 ≤ft(4/x )+C

Solution

Let x=4 , dx=4 ,d , sqrt(x2-16)=4 . Then 4 /4 ·4 ,d =4 2 ,d =4( - )+C. With = sqrt(x2-16)4 and = 4x: sqrt(x2-16)-4 4/x+C for x>4.

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