Engineering Board Exam Reviewer · Alternating Current and Voltage · medium
The sinusoidal voltage shown has a period of 12 ms and a peak value of 50 V. What is its instantaneous value at t=1.5 ms?
- 25 V
- 70.7 V
- 17.7 V
- 35.4 V
Answer
D. 35.4 V
Solution
The angle reached is =360°·t/T=360°· 1.5 ms12 ms=45°. v=Vp =50 V 45°=35.4 V.
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