Engineering Board Exam Reviewer · Alternating Current and Voltage · medium
The waveform shown is a full-wave rectified sine voltage. Find its average (dc) value.
- 15.9 V
- 31.8 V
- 35.4 V
- 25 V
Answer
B. 31.8 V
Solution
The peak is 50 V. For a full-wave rectified sine, Vavg=2Vp/π=0.637Vp=0.637(50 V)=31.8 V.
More Alternating Current and Voltage questions
- The waveform shown is a half-wave rectified sine voltage. Find its average (dc) value over a complete cycle.
- Find the rms value of the triangle wave shown.
- What is the rms value of the symmetrical square wave shown?
- Two sinusoids of the same frequency are plotted below: a voltage v (solid) and a current i (dashed). Use the time axis (milliseconds, one…
- The voltage v (solid) and the current i (dashed) plotted below have the same frequency. What is their phase relationship? (The time axis…
- The sinusoidal voltage shown has a period of 12 ms and a peak value of 50 V. What is its instantaneous value at t=1.5 ms?
- Which expression describes the voltage waveform shown?
- What is the average value of a sine wave over one complete cycle?
- A sinusoidal voltage has a peak value of 311 V. What is its rms value?
- A voltmeter reads 120 V on an ac line. What is the peak value of the voltage?