Engineering Board Exam Reviewer · Circuit Theorems and Conversions · hard
In the circuit shown, V=48 V, R1=10, , R2=2, , and RL=5, . Use Thevenin's theorem to find the power dissipated by RL.
- 12.8 W
- 7.2 W
- 9.6 W
- 14.4 W
Answer
B. 7.2 W
Solution
Thevenin equivalent seen by RL: VTh=VR2/R1+R2=8 V and RTh=R1 R2=1.67, . IL= VThRTh+RL=1.2 A, so PL=IL2RL=(1.2 A)2(5, )=7.2 W.
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