Engineering Board Exam Reviewer · Engineering Materials · hard
For a 0.25% C steel just below 727 °C, what is the TOTAL mass fraction of ferrite (proeutectoid plus eutectoid)? (ferrite 0.022% C, cementite 6.70% C)
- 0.966
- 0.691
- 0.034
- 0.750
Answer
A. 0.966
Solution
Wα,total = (6.70 - 0.25)/(6.70 - 0.022) = 0.966.
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