Engineering Board Exam Reviewer · Engineering Materials · hard
What is the planar density of atoms on the (100) plane of copper (FCC, a = 0.3615 nm)?
- 1.53 × 1019 atoms/m²
- 7.65 × 1018 atoms/m²
- 3.06 × 1019 atoms/m²
- 1.08 × 1019 atoms/m²
Answer
A. 1.53 × 1019 atoms/m²
Solution
The (100) face of an FCC cell contains 4 × 1/4 + 1 = 2 atoms in an area a2. PD = 2/(0.3615 × 10-9)2 = 1.53 × 1019 atoms/m².
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