Engineering Board Exam Reviewer · Chemistry · hard

What is the percent ionization of 0.1 M acetic acid? (Ka = 1.8 × 10-5)

1. 100.00%
2. 0.018%
3. 13.4%
4. 1.34%

Answer

D. 1.34%

Solution

[H+] Ka C = 1.34 × 10-3 M. % ionization = 1.34 × 10-3/0.1 × 100 = 1.34%.

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