Engineering Board Exam Reviewer · Chemistry · hard
What mass of CO2 is released when 200 g of limestone that is 80% CaCO₃ is completely decomposed? (CaCO₃ CaO + CO2) (Use H = 1, C = 12, N = 14, O = 16, Na = 23, S = 32, Cl = 35.5, Ca = 40)
- 88.0 g
- 89.6 g
- 70.4 g
- 17.6 g
Answer
C. 70.4 g
Solution
Pure CaCO₃ = 0.8(200) = 160 g = 1.6 mol 1.6 mol CO2 × 44 = 70.4 g.
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