Engineering Board Exam Reviewer · Chemistry · hard
For the cell Zn | Zn2+(1.0 M) || Cu2+(0.01 M) | Cu at 25 °C, what is the cell potential? (E°cell = 1.10 V)
- 1.1000 V
- 1.1592 V
- 0.9816 V
- 1.0408 V
Answer
D. 1.0408 V
Solution
Nernst: E = E° - (0.0592/n) Q, Q = [Zn2+]/[Cu2+] = 100. E = 1.10 - (0.0296)(2) = 1.0408 V.
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