Engineering Board Exam Reviewer · Physics · hard
A ball is thrown horizontally at 25 m/s from the top of a cliff 80 m high. How far from the base of the cliff does it land? (g = 9.81 m/s2)
- 100.96 m
- 203.87 m
- 71.39 m
- 80.00 m
Answer
A. 100.96 m
Solution
t = sqrt(2h/g) = sqrt(160/9.81) = 4.039 s. x = v0t = 25(4.039) = 100.96 m.
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