Engineering Board Exam Reviewer · Fluid Mechanics · hard
An open cylinder 0.6 m in diameter, partly filled with water, is rotated at 120 rpm about its vertical axis. By how much does the water at the rim rise above the original level? (no spilling)
- 0.7244 m
- 0.3622 m
- 0.1811 m
- 0.0661 m
Answer
B. 0.3622 m
Solution
= 120(2π /60) = 12.566 rad/s. Paraboloid height h = 2r2/2g = 0.7244 m. Since the paraboloid volume is half the cylinder, the rim rises h/2 = 0.3622 m above the original level.
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