Engineering Board Exam Reviewer · Fluid Mechanics · hard
A rectangular barge 6 m long and 2.4 m wide floats with a draft of 0.8 m. Its center of gravity is 0.8 m above the bottom. What is its metacentric height?
- 0.200 m
- 0.600 m
- -0.200 m
- 1.000 m
Answer
A. 0.200 m
Solution
Vd = 6(2.4)(0.8) = 11.520 m3; I = LB3/12 = 6.9120 m4; BM = I/Vd = 0.600 m. KB = 0.4 m. GM = KB + BM - KG = 0.4 + 0.600 - 0.8 = 0.200 m (> 0, stable).
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