Engineering Board Exam Reviewer · Fluid Mechanics · medium
A pump delivers 50 L/s of water against a total head of 30 m. If the pump efficiency is 75%, what is the power input?
- 14.72 kW
- 19.62 kW
- 11.04 kW
- 196.20 kW
Answer
B. 19.62 kW
Solution
P = QH/ = 9.81(0.05)(30)/0.75 = 19.62 kW.
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