Engineering Board Exam Reviewer · Thermodynamics · hard
A tank contains a liquid-vapor mixture of water at 100 kPa with a specific volume of 0.5 m3/kg. If vf = 0.001043 m3/kg and vg = 1.694 m3/kg, what is the quality?
- 0.2952
- 0.7053
- 0.2947
- 0.2950
Answer
C. 0.2947
Solution
x = (v - vf)/(vg - vf) = (0.5 - 0.001043)/(1.694 - 0.001043) = 0.2947.
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