Engineering Board Exam Reviewer · Strength of Materials · hard
A rigid plate distributes an axial load of 120 kN equally in strain to a steel rod (A = 500 mm2, E = 200 GPa) and an aluminum rod (A = 600 mm2, E = 70 GPa) acting in parallel. How much of the load is carried by the steel rod?
- 54.55
- 60
- 88.89
- 84.51
Answer
D. 84.51
Solution
Equal deformation requires P1/(A1E1) = P2/(A2E2). Steel share = P(A1E1)/(A1E1 + A2E2) = 120(500 × 200) / (500 × 200 + 600 × 70) = 84.51 kN.
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