Engineering Board Exam Reviewer · Strength of Materials · hard
A solid 50-mm diameter shaft transmits 60 kW at 900 rpm. What is the maximum shear stress developed in the shaft?
- 25.94
- 51.88
- 12.97
- 2.72
Answer
A. 25.94
Solution
T = 60P/(2π n) = 60(60 × 1000)/(2π × 900) = 636.62 N· m. max = 16T/(π d3) = 16(636619.77 N· mm)/(π (50)3) = 25.94 MPa.
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