Engineering Board Exam Reviewer · Engineering Mechanics · easy
A 18 kg block rests on a horizontal surface with a coefficient of friction of 0.4. What is the minimum horizontal force required to start moving the block?
- 70.63
- 441.45
- 7.2
- 105.95
Answer
A. 70.63
Solution
Weight W = mg = 18 × 9.81 = 176.58 N. Since the surface is horizontal, N = W. Maximum static friction Ff = N = 0.4 × 176.58 = 70.63 N.
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