Engineering Board Exam Reviewer · Engineering Mechanics · medium

A particle starts with an initial velocity of 6 m/s and a constant acceleration of 2.5 m/s2. What distance does it travel in 6 seconds?

  1. 126
  2. 81
  3. 36
  4. 40.5

Answer

B. 81

Solution

s = v0t + 1/2at2 = (6)(6) + 1/2(2.5)(6)2 = 81 m.

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