Engineering Board Exam Reviewer · Engineering Mechanics · medium
A particle starts with an initial velocity of 4 m/s and a constant acceleration of 1.5 m/s2. What distance does it travel in 4 seconds?
- 40
- 28
- 16
- 14
Answer
B. 28
Solution
s = v0t + 1/2at2 = (4)(4) + 1/2(1.5)(4)2 = 28 m.
More Engineering Mechanics questions
- A car starts with an initial velocity of 5 m/s and accelerates uniformly at 2 m/s2 for 3 seconds. What is its final velocity?
- A reference frame in which Newton's laws of motion hold true without correction is called a(n):
- In dynamics, D'Alembert's principle allows a dynamic problem to be treated as a static equilibrium problem by introducing:
- According to Newton's first law (law of inertia), a body at rest or in uniform motion will remain so unless:
- Kinematics differs from kinetics in that kinematics:
- Mass and weight differ in that:
- Inertia refers to a body's:
- Which of Newton's laws states that the acceleration of a body is directly proportional to the net force acting on it and inversely…
- Dynamics is the branch of mechanics concerned with:
- A semicircular area has a radius of 3.2 m. What is the distance of its centroid from the flat (diameter) edge?