Engineering Board Exam Reviewer · Engineering Mechanics · medium
A particle starts with an initial velocity of 8 m/s and a constant acceleration of 3.5 m/s2. What distance does it travel in 8 seconds?
- 288
- 176
- 64
- 88
Answer
B. 176
Solution
s = v0t + 1/2at2 = (8)(8) + 1/2(3.5)(8)2 = 176 m.
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