Engineering Board Exam Reviewer · Laplace Transforms · medium
Find the Laplace transform of f(t)= 2t.
- 1s2 + 1
- 2s2 + 4
- 2s ≤ft(s2 + 4 )
- 1s ≤ft(s2 + 4 )
Answer
C. 2s ≤ft(s2 + 4 )
Solution
2t=1- 2t/2, so L 2t= 12≤ft( 1s-s/s2+4 )= 12·4/s(s2+4)=2/s(s2+4).
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