Engineering Board Exam Reviewer · Laplace Transforms · medium
Find the Laplace transform of f(t)=te2t.
- 1≤ft(s + 2 )2
- 1s2 - 4
- 2≤ft(s - 2 )3
- 1≤ft(s - 2 )2
Answer
D. 1≤ft(s - 2 )2
Solution
Lt= 1s2. By the first shifting theorem, replace s with s-2: Lte2t=1/(s-2)2.
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