Engineering Board Exam Reviewer · Complex Numbers: Operations · easy

Evaluate (1+i)8.

1. 8
2. 256
3. 16
4. -16

Answer

C. 16

Solution

(1+i)2=1+2i+i2=2i. Then (1+i)8=(2i)4=16i4=16.

More Complex Numbers: Operations questions

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2. Simplify (3+2i)(4-5i).
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5. Add: (3+5i)+(2-7i)
6. Multiply: (4+3i)(2-i)
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8. Find the absolute value (modulus) of 5-12i.
9. Find the complex conjugate of 6-8i, then multiply it by the original number.
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