Engineering Board Exam Reviewer · Complex Numbers: Operations · easy

Simplify: i2001

1. i
2. -i
3. 1
4. -1

Answer

A. i

Solution

Since 2000 is divisible by 4, i2001=i2000· i=1· i=i.

More Complex Numbers: Operations questions

1. Simplify: i15+i18
2. Add: (3+5i)+(2-7i)
3. Multiply: (4+3i)(2-i)
4. Divide: 3+4i/1-2i
5. Find the absolute value (modulus) of 5-12i.
6. Find the complex conjugate of 6-8i, then multiply it by the original number.
7. Simplify: (2+3i)2

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