Engineering Board Exam Reviewer · Binomial Distribution · medium
A basketball player makes 80% of free throws. In 5 attempts, what is the probability of making at least 4?
- 0.4096
- 0.3277
- 0.7373
- 0.2627
Answer
C. 0.7373
Solution
P(X≥4)=P(4)+P(5)= 54(0.8)4(0.2)+(0.8)5=0.4096+0.32768=0.7373.
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