Engineering Board Exam Reviewer · Binomial Distribution · medium

A basketball player makes 70% of his free throws. If he attempts 4 free throws, what is the probability that he makes exactly 3?

1. 0.4116
2. 0.343
3. 0.2401
4. 0.504

Answer

A. 0.4116

Solution

P= 43(0.7)3(0.3)1=4(0.343)(0.3)=0.4116.

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