Engineering Board Exam Reviewer · Equations of Lines · medium
Find the equation of the line through point (3,1) and is perpendicular to the line x+5y+5=0.
- 5x-2y=14
- 5x-y=14
- 2x-5y=14
- 2x+5y=14
Answer
B. 5x-y=14
Solution
x+5y+5=0 has slope -1/5, so the perpendicular slope is 5. Line thru (3,1): y-1=5(x-3), giving 5x-y=14.
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