Engineering Board Exam Reviewer · Equations of Lines · medium
Find the equation of the perpendicular bisector of the line joining (5,0) and (-7,3).
- 8x+2y+11=0
- 8x-2y+11=0
- 8x-y+11=0
- 8x+y+11=0
Answer
B. 8x-2y+11=0
Solution
The midpoint of (5,0) and (-7,3) is (-1, 1.5). The segment's slope is -1/4, so the perpendicular bisector's slope is 4. Line: y-1.5=4(x+1), which simplifies to 8x-2y+11=0.
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