Engineering Board Exam Reviewer · Inverse Trigonometric Functions · medium

Evaluate 1+ 2+ 3 in degrees.

  1. 135°
  2. 180°
  3. 90°
  4. 225°

Answer

B. 180°

Solution

Let = 2+ 3. =2+3/1-6=-1 with in Quadrant II, so =135°. Adding 1=45° gives 180°.

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