Engineering Board Exam Reviewer · Inverse Trigonometric Functions · easy

CE Board November 1992: Find the value of ≤ft( 15/17 ).

  1. 8/11
  2. 8/19
  3. 8/15
  4. 8/17

Answer

D. 8/17

Solution

If A=15/17, then A=sqrt(1-≤ft(15/17 )2)=sqrt(64/289)=8/17.

More Inverse Trigonometric Functions questions

  1. ME Board April 1998: ≤ft[2 ≤ft( 3/2 ) ] is equal to
  2. EE Board October 1992: Evaluate arccot[2 ( 0.5)]
  3. ECE Board March 1996: Solve for x in the given equation: (2x) + (x) = π/4
  4. EE Board March 1998: Solve for x in the equation: (x+1) + (x-1) = (12).
  5. Solve for x: 2x+ 3x= π4.
  6. Solve for x: x=2 x.
  7. Evaluate 1+ 2+ 3 in degrees.
  8. Find ≤ft(2 35 ).
  9. Find ≤ft( 35 ).
  10. Find ≤ft( 3+ 2 ).

All Inverse Trigonometric Functions questions