Engineering Board Exam Reviewer · Nonhomogeneous Second-Order Equations · medium
Find the general solution of y''+4y=8e2x.
- y = C1 2 x + C2 2 x + 2 e2 x
- y = C1 2 x + C2 2 x + e2 x2
- y = C1 2 x + C2 2 x + x e2 x
- y = C1 2 x + C2 2 x + e2 x
Answer
D. y = C1 2 x + C2 2 x + e2 x
Solution
Complementary: yc=C1 2x+C2 2x. Try yp=Ae2x: 4A+4A=8 A=1. So y=C1 2x+C2 2x+e2x.
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