Engineering Board Exam Reviewer · Nonhomogeneous Second-Order Equations · hard
Use variation of parameters to solve y''+y= x for 0<x< π2.
- y = C1 x + C2 x + x x - ≤ft( x ) x
- y = C1 x + C2 x + x x + ≤ft( x ) x
- y = C1 x + C2 x - x x + ≤ft( x ) x
- y = C1 x + C2 x + x x + ≤ft( x ) x
Answer
B. y = C1 x + C2 x + x x + ≤ft( x ) x
Solution
y1= x, y2= x, W=1. Then u1'=-y2 x/W=- x u1= ( x) and u2'=y1 x/W=1 u2=x. So yp= x ( x)+x x and y=C1 x+C2 x+ x ( x)+x x.
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