Engineering Board Exam Reviewer · Integration by Parts · hard

Evaluate: ≤ft( x ),dx (assume x>0)

1. x ≤ft( ≤ft( x ) - ≤ft( x ) )2+C
2. x ≤ft( ≤ft( x ) + ≤ft( x ) )2+C
3. x ≤ft( ≤ft( x ) - ≤ft( x ) )+C
4. x ≤ft( x )2+C

Answer

A. x ≤ft( ≤ft( x ) - ≤ft( x ) )2+C

Solution

Parts twice gives I=x ( x)-x ( x)-I, so I=x≤ft[ ( x)- ( x) ]/2+C.

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