Engineering Board Exam Reviewer · Integration by Parts · medium
Evaluate: x,ex,dx
- xex-ex+C
- xex+C
- ex+C
- x2/2ex+C
Answer
A. xex-ex+C
Solution
Let u=x, dv=ex,dx. xex- ex,dx=xex-ex+C.
Engineering Board Exam Reviewer · Integration by Parts · medium
A. xex-ex+C
Let u=x, dv=ex,dx. xex- ex,dx=xex-ex+C.