Engineering Board Exam Reviewer · Indefinite Integrals - Basic Formulas · easy

Evaluate: x3 - 3 x + 2x2,dx (assume x>0)

1. x22 - 3 x - 2/x+C
2. x22 + 3 x - 2/x+C
3. x22 - 3 x + 2/x+C
4. x22 - 2 x - 3/x+C

Answer

A. x22 - 3 x - 2/x+C

Solution

Divide term by term: x3-3x+2/x2=x- 3x+2/x2. Integrating: x2/2-3 x-2/x+C for x>0.

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