Engineering Board Exam Reviewer · Indefinite Integrals - Basic Formulas · easy
Evaluate: ≤ft(sqrt(x) + 1sqrt(x) )2,dx (assume x>0)
- x22 + 2 x + x+C
- x22 + 2 x - x+C
- x22 + 2 x + 1/x+C
- x2 + 2 x + x+C
Answer
A. x22 + 2 x + x+C
Solution
Expand first: ≤ft(sqrt(x)+ 1sqrt(x) )2=x+2+1/x. Then ≤ft(x+2+1/x )dx=x2/2+2x+ x+C for x>0.
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