Engineering Board Exam Reviewer · Curve Analysis: Critical Points, Concavity, and Inflection · medium

Find the absolute maximum value of f(x)=x3-3x on the interval [0,2].

  1. 0
  2. -2
  3. 2
  4. 1

Answer

C. 2

Solution

f'(x)=3x2-3=0 x=1. Compare f(0)=0, f(1)=-2, and f(2)=8-6=2. The absolute maximum is 2.

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