Engineering Board Exam Reviewer · Derivatives of Inverse Trigonometric Functions · medium

Find y' if y= 1x (x>1).

1. - 1x x2 - 1
2. 1x x2 - 1
3. 1 x2 - 1
4. 1x2 x2 - 1

Answer

B. 1x x2 - 1

Solution

y'=- 1sqrt(1-1/x2)·≤ft(- 1x2 )= 1x2sqrt((x2-1)/x2)= 1xsqrt(x2-1) for x>1.

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