Engineering Board Exam Reviewer · Derivatives of Inverse Trigonometric Functions · hard

Find y' if y= 1+x/1-x.

1. 2x2 + 1
2. 1≤ft(x2 + 1 )2
3. 1x2 + 1
4. 11 - x2

Answer

C. 1x2 + 1

Solution

With u=1+x/1-x: u'=(1-x)+(1+x)/(1-x)2=2/(1-x)2 and 1+u2=(1-x)2+(1+x)2/(1-x)2=2(1+x2)/(1-x)2. So y'=u'/1+u2=1/1+x2.

More Derivatives of Inverse Trigonometric Functions questions

1. Find y' if y= 1x (x>1).
2. Find y' if y=x x.
3. Find y' if y= (2x).
4. Differentiate y= (2x).
5. Find y' if y= ≤ft(x/3 ).
6. Differentiate y= (x2).

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