Engineering Board Exam Reviewer · Special Limits and Indeterminate Forms · medium
Evaluate x ∞x2e-x.
- 1
- ∞
- 0
- 2
Answer
C. 0
Solution
Write x2e-x=x2/ex, which is ∞∞. Applying L'Hôpital's rule twice: 2x/ex 2/ex 0.
Engineering Board Exam Reviewer · Special Limits and Indeterminate Forms · medium
C. 0
Write x2e-x=x2/ex, which is ∞∞. Applying L'Hôpital's rule twice: 2x/ex 2/ex 0.