Engineering Board Exam Reviewer · Special Limits and Indeterminate Forms · medium
Evaluate x 01- 2x/x2.
- 1
- 2
- 0
- 4
Answer
B. 2
Solution
This is 00. Apply L'Hôpital's rule: 2 2x/2x= 2x/x=2 (or apply the rule again: 4 2x/2=2).
Engineering Board Exam Reviewer · Special Limits and Indeterminate Forms · medium
B. 2
This is 00. Apply L'Hôpital's rule: 2 2x/2x= 2x/x=2 (or apply the rule again: 4 2x/2=2).