Engineering Board Exam Reviewer · Sequences and Series · medium
Let x1=97, x2=2/x1, x3=3/x2, x4=4/x3, , x8=8/x7. Find x1 · x2 ·s x8.
- 201
- 471
- 384
- 123
Answer
C. 384
Solution
x1 x2 ·s x8 = (x1)≤ft(2/x1 )(x3)≤ft(4/x3 )(x5)≤ft(6/x5 )(x7)≤ft(8/x7 ) = 2 · 4 · 6 · 8 = 384.
More Sequences and Series questions
- The pages of a book are numbered 1 through n. When the page numbers of the book were added, one of the page numbers was mistakenly added…
- What is the first four terms of the sequence whose general term is n2+1?
- Find the sum of the first 5 terms in the sequence whose general term is 2n-1.
- Determine the 5th term of the sequence whose sum of n terms is given by (2n+3-5).
- Find the 30th term of the arithmetic progression 4, 7, 10,
- Four positive integers form an arithmetic progression. If the product of the 1st and the last term is 70 and the product of the 2nd and…
- How many terms of the progression 3, 5, 7, should there be so that their sum will be 2600?
- What is the sum of all odd integers between 10 and 500?
- What is the sum of all even integers from 10 to 500?
- Solve for x in the following equation: x+4x+7x+·s+64x=1430.