Engineering Board Exam Reviewer · Sequences and Series · medium
How many terms of the progression 3, 5, 7, should there be so that their sum will be 2600?
- 60
- 50
- 40
- 20
Answer
B. 50
Solution
Using S=n/2(2a+(n-1)d) with a=3, d=2 simplifies to n(n+2)=2600, giving n=50.
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