Engineering Board Exam Reviewer · RC Circuits · medium
In the series RC circuit shown, a 255 V (rms) source with =2000 rad/s is connected to R=150, and C=6.25, F. Find the real power dissipated by the circuit.
- 382 W
- 180 W
- 338 W
- 434 W
Answer
C. 338 W
Solution
XC=1/ C= 1(2000)(6.25, F)=80, . |Z|=sqrt(R2+XC2)=sqrt((150, )2+(80, )2)=170, . I=V/|Z|= 255 V170, =1.5 A. Only the resistor dissipates real power: P=I2R=(1.5 A)2(150, )=338 W.
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