Engineering Board Exam Reviewer · Ohm's Law · medium
A 4.7 k resistor carries 2.5 mA. What is the voltage across it?
- 11.75 V
- 1.88 V
- 0.53 V
- 4.7 V
Answer
A. 11.75 V
Solution
V=IR=(2.5×10-3)(4.7×103)=11.75 V.
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