Engineering Board Exam Reviewer · Environmental Engineering · medium
A sedimentation tank 30 m long, 10 m wide and 4 m deep treats 0.25 m3/s of water. What is its detention time?
- 80 hours
- 0.333 hours
- 1.33 hours
- 0.33 hours
Answer
C. 1.33 hours
Solution
t = V/Q = (30 × 10 × 4)/0.25 = 4800 s = 1.33 hours.
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